Integrand size = 24, antiderivative size = 270 \[ \int \frac {\sqrt [4]{12-3 e^2 x^2}}{(2+e x)^{3/2}} \, dx=-\frac {4 \sqrt [4]{3} \sqrt [4]{2-e x}}{e \sqrt [4]{2+e x}}-\frac {\sqrt {2} \sqrt [4]{3} \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{2+e x}}\right )}{e}+\frac {\sqrt {2} \sqrt [4]{3} \arctan \left (1+\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{2+e x}}\right )}{e}-\frac {\sqrt [4]{3} \log \left (\frac {\sqrt {6-3 e x}-\sqrt {6} \sqrt [4]{2-e x} \sqrt [4]{2+e x}+\sqrt {3} \sqrt {2+e x}}{\sqrt {2+e x}}\right )}{\sqrt {2} e}+\frac {\sqrt [4]{3} \log \left (\frac {\sqrt {6-3 e x}+\sqrt {6} \sqrt [4]{2-e x} \sqrt [4]{2+e x}+\sqrt {3} \sqrt {2+e x}}{\sqrt {2+e x}}\right )}{\sqrt {2} e} \]
-4*3^(1/4)*(-e*x+2)^(1/4)/e/(e*x+2)^(1/4)-1/2*3^(1/4)*ln(3^(1/2)-(-e*x+2)^ (1/4)*6^(1/2)/(e*x+2)^(1/4)+3^(1/2)*(-e*x+2)^(1/2)/(e*x+2)^(1/2))/e*2^(1/2 )+1/2*3^(1/4)*ln(3^(1/2)+(-e*x+2)^(1/4)*6^(1/2)/(e*x+2)^(1/4)+3^(1/2)*(-e* x+2)^(1/2)/(e*x+2)^(1/2))/e*2^(1/2)+3^(1/4)*arctan(-1+(-e*x+2)^(1/4)*2^(1/ 2)/(e*x+2)^(1/4))/e*2^(1/2)+3^(1/4)*arctan(1+(-e*x+2)^(1/4)*2^(1/2)/(e*x+2 )^(1/4))/e*2^(1/2)
Time = 0.67 (sec) , antiderivative size = 151, normalized size of antiderivative = 0.56 \[ \int \frac {\sqrt [4]{12-3 e^2 x^2}}{(2+e x)^{3/2}} \, dx=\frac {\sqrt [4]{3} \left (-4 \sqrt [4]{4-e^2 x^2}+\sqrt {4+2 e x} \arctan \left (\frac {\sqrt {4+2 e x} \sqrt [4]{4-e^2 x^2}}{2+e x-\sqrt {4-e^2 x^2}}\right )+\sqrt {4+2 e x} \text {arctanh}\left (\frac {2+e x+\sqrt {4-e^2 x^2}}{\sqrt {4+2 e x} \sqrt [4]{4-e^2 x^2}}\right )\right )}{e \sqrt {2+e x}} \]
(3^(1/4)*(-4*(4 - e^2*x^2)^(1/4) + Sqrt[4 + 2*e*x]*ArcTan[(Sqrt[4 + 2*e*x] *(4 - e^2*x^2)^(1/4))/(2 + e*x - Sqrt[4 - e^2*x^2])] + Sqrt[4 + 2*e*x]*Arc Tanh[(2 + e*x + Sqrt[4 - e^2*x^2])/(Sqrt[4 + 2*e*x]*(4 - e^2*x^2)^(1/4))]) )/(e*Sqrt[2 + e*x])
Time = 0.37 (sec) , antiderivative size = 216, normalized size of antiderivative = 0.80, number of steps used = 14, number of rules used = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.542, Rules used = {456, 57, 27, 73, 770, 755, 1476, 1082, 217, 1479, 25, 27, 1103}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\sqrt [4]{12-3 e^2 x^2}}{(e x+2)^{3/2}} \, dx\) |
\(\Big \downarrow \) 456 |
\(\displaystyle \int \frac {\sqrt [4]{6-3 e x}}{(e x+2)^{5/4}}dx\) |
\(\Big \downarrow \) 57 |
\(\displaystyle -3 \int \frac {1}{3^{3/4} (2-e x)^{3/4} \sqrt [4]{e x+2}}dx-\frac {4 \sqrt [4]{3} \sqrt [4]{2-e x}}{e \sqrt [4]{e x+2}}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle -\sqrt [4]{3} \int \frac {1}{(2-e x)^{3/4} \sqrt [4]{e x+2}}dx-\frac {4 \sqrt [4]{3} \sqrt [4]{2-e x}}{e \sqrt [4]{e x+2}}\) |
\(\Big \downarrow \) 73 |
\(\displaystyle \frac {4 \sqrt [4]{3} \int \frac {1}{\sqrt [4]{e x+2}}d\sqrt [4]{2-e x}}{e}-\frac {4 \sqrt [4]{3} \sqrt [4]{2-e x}}{e \sqrt [4]{e x+2}}\) |
\(\Big \downarrow \) 770 |
\(\displaystyle \frac {4 \sqrt [4]{3} \int \frac {1}{3-e x}d\frac {\sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}}{e}-\frac {4 \sqrt [4]{3} \sqrt [4]{2-e x}}{e \sqrt [4]{e x+2}}\) |
\(\Big \downarrow \) 755 |
\(\displaystyle \frac {4 \sqrt [4]{3} \left (\frac {1}{2} \int \frac {1-\sqrt {2-e x}}{3-e x}d\frac {\sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+\frac {1}{2} \int \frac {\sqrt {2-e x}+1}{3-e x}d\frac {\sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}\right )}{e}-\frac {4 \sqrt [4]{3} \sqrt [4]{2-e x}}{e \sqrt [4]{e x+2}}\) |
\(\Big \downarrow \) 1476 |
\(\displaystyle \frac {4 \sqrt [4]{3} \left (\frac {1}{2} \int \frac {1-\sqrt {2-e x}}{3-e x}d\frac {\sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+\frac {1}{2} \left (\frac {1}{2} \int \frac {1}{\sqrt {2-e x}-\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+1}d\frac {\sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+\frac {1}{2} \int \frac {1}{\sqrt {2-e x}+\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+1}d\frac {\sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}\right )\right )}{e}-\frac {4 \sqrt [4]{3} \sqrt [4]{2-e x}}{e \sqrt [4]{e x+2}}\) |
\(\Big \downarrow \) 1082 |
\(\displaystyle \frac {4 \sqrt [4]{3} \left (\frac {1}{2} \left (\frac {\int \frac {1}{-\sqrt {2-e x}-1}d\left (1-\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}\right )}{\sqrt {2}}-\frac {\int \frac {1}{-\sqrt {2-e x}-1}d\left (\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+1\right )}{\sqrt {2}}\right )+\frac {1}{2} \int \frac {1-\sqrt {2-e x}}{3-e x}d\frac {\sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}\right )}{e}-\frac {4 \sqrt [4]{3} \sqrt [4]{2-e x}}{e \sqrt [4]{e x+2}}\) |
\(\Big \downarrow \) 217 |
\(\displaystyle \frac {4 \sqrt [4]{3} \left (\frac {1}{2} \int \frac {1-\sqrt {2-e x}}{3-e x}d\frac {\sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+\frac {1}{2} \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}\right )}{\sqrt {2}}\right )\right )}{e}-\frac {4 \sqrt [4]{3} \sqrt [4]{2-e x}}{e \sqrt [4]{e x+2}}\) |
\(\Big \downarrow \) 1479 |
\(\displaystyle \frac {4 \sqrt [4]{3} \left (\frac {1}{2} \left (-\frac {\int -\frac {\sqrt {2}-\frac {2 \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}}{\sqrt {2-e x}-\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+1}d\frac {\sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}}{2 \sqrt {2}}-\frac {\int -\frac {\sqrt {2} \left (\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+1\right )}{\sqrt {2-e x}+\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+1}d\frac {\sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}}{2 \sqrt {2}}\right )+\frac {1}{2} \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}\right )}{\sqrt {2}}\right )\right )}{e}-\frac {4 \sqrt [4]{3} \sqrt [4]{2-e x}}{e \sqrt [4]{e x+2}}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle \frac {4 \sqrt [4]{3} \left (\frac {1}{2} \left (\frac {\int \frac {\sqrt {2}-\frac {2 \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}}{\sqrt {2-e x}-\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+1}d\frac {\sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}}{2 \sqrt {2}}+\frac {\int \frac {\sqrt {2} \left (\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+1\right )}{\sqrt {2-e x}+\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+1}d\frac {\sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}}{2 \sqrt {2}}\right )+\frac {1}{2} \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}\right )}{\sqrt {2}}\right )\right )}{e}-\frac {4 \sqrt [4]{3} \sqrt [4]{2-e x}}{e \sqrt [4]{e x+2}}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {4 \sqrt [4]{3} \left (\frac {1}{2} \left (\frac {\int \frac {\sqrt {2}-\frac {2 \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}}{\sqrt {2-e x}-\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+1}d\frac {\sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}}{2 \sqrt {2}}+\frac {1}{2} \int \frac {\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+1}{\sqrt {2-e x}+\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+1}d\frac {\sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}\right )+\frac {1}{2} \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}\right )}{\sqrt {2}}\right )\right )}{e}-\frac {4 \sqrt [4]{3} \sqrt [4]{2-e x}}{e \sqrt [4]{e x+2}}\) |
\(\Big \downarrow \) 1103 |
\(\displaystyle \frac {4 \sqrt [4]{3} \left (\frac {1}{2} \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+1\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}\right )}{\sqrt {2}}\right )+\frac {1}{2} \left (\frac {\log \left (\sqrt {2-e x}+\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+1\right )}{2 \sqrt {2}}-\frac {\log \left (\sqrt {2-e x}-\frac {\sqrt {2} \sqrt [4]{2-e x}}{\sqrt [4]{e x+2}}+1\right )}{2 \sqrt {2}}\right )\right )}{e}-\frac {4 \sqrt [4]{3} \sqrt [4]{2-e x}}{e \sqrt [4]{e x+2}}\) |
(-4*3^(1/4)*(2 - e*x)^(1/4))/(e*(2 + e*x)^(1/4)) + (4*3^(1/4)*((-(ArcTan[1 - (Sqrt[2]*(2 - e*x)^(1/4))/(2 + e*x)^(1/4)]/Sqrt[2]) + ArcTan[1 + (Sqrt[ 2]*(2 - e*x)^(1/4))/(2 + e*x)^(1/4)]/Sqrt[2])/2 + (-1/2*Log[1 + Sqrt[2 - e *x] - (Sqrt[2]*(2 - e*x)^(1/4))/(2 + e*x)^(1/4)]/Sqrt[2] + Log[1 + Sqrt[2 - e*x] + (Sqrt[2]*(2 - e*x)^(1/4))/(2 + e*x)^(1/4)]/(2*Sqrt[2]))/2))/e
3.10.32.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + 1))), x] - Simp[d*(n/(b*(m + 1))) Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d}, x] & & GtQ[n, 0] && LtQ[m, -1] && !(IntegerQ[n] && !IntegerQ[m]) && !(ILeQ[m + n + 2, 0] && (FractionQ[m] || GeQ[2*n + m + 1, 0])) && IntLinearQ[a, b, c , d, m, n, x]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ {p = Denominator[m]}, Simp[p/b Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL inearQ[a, b, c, d, m, n, x]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( -1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & & (LtQ[a, 0] || LtQ[b, 0])
Int[((c_) + (d_.)*(x_))^(n_)*((a_) + (b_.)*(x_)^2)^(p_.), x_Symbol] :> Int[ (c + d*x)^(n + p)*(a/c + (b/d)*x)^p, x] /; FreeQ[{a, b, c, d, n, p}, x] && EqQ[b*c^2 + a*d^2, 0] && (IntegerQ[p] || (GtQ[a, 0] && GtQ[c, 0] && !Integ erQ[n]))
Int[((a_) + (b_.)*(x_)^4)^(-1), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2] ], s = Denominator[Rt[a/b, 2]]}, Simp[1/(2*r) Int[(r - s*x^2)/(a + b*x^4) , x], x] + Simp[1/(2*r) Int[(r + s*x^2)/(a + b*x^4), x], x]] /; FreeQ[{a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] & & AtomQ[SplitProduct[SumBaseQ, b]]))
Int[((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[a^(p + 1/n) Subst[In t[1/(1 - b*x^n)^(p + 1/n + 1), x], x, x/(a + b*x^n)^(1/n)], x] /; FreeQ[{a, b}, x] && IGtQ[n, 0] && LtQ[-1, p, 0] && NeQ[p, -2^(-1)] && IntegerQ[p + 1 /n]
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S implify[a*(c/b^2)]}, Simp[-2/b Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b )], x] /; RationalQ[q] && (EqQ[q^2, 1] || !RationalQ[b^2 - 4*a*c])] /; Fre eQ[{a, b, c}, x]
Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 2*(d/e), 2]}, Simp[e/(2*c) Int[1/Simp[d/e + q*x + x^2, x], x], x] + Simp[ e/(2*c) Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ -2*(d/e), 2]}, Simp[e/(2*c*q) Int[(q - 2*x)/Simp[d/e + q*x - x^2, x], x], x] + Simp[e/(2*c*q) Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /; F reeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]
\[\int \frac {\left (-3 x^{2} e^{2}+12\right )^{\frac {1}{4}}}{\left (e x +2\right )^{\frac {3}{2}}}d x\]
Result contains complex when optimal does not.
Time = 0.32 (sec) , antiderivative size = 321, normalized size of antiderivative = 1.19 \[ \int \frac {\sqrt [4]{12-3 e^2 x^2}}{(2+e x)^{3/2}} \, dx=\frac {3^{\frac {1}{4}} {\left (e^{2} x + 2 \, e\right )} \left (-\frac {1}{e^{4}}\right )^{\frac {1}{4}} \log \left (\frac {3^{\frac {1}{4}} {\left (e^{2} x + 2 \, e\right )} \left (-\frac {1}{e^{4}}\right )^{\frac {1}{4}} + {\left (-3 \, e^{2} x^{2} + 12\right )}^{\frac {1}{4}} \sqrt {e x + 2}}{e x + 2}\right ) - 3^{\frac {1}{4}} {\left (e^{2} x + 2 \, e\right )} \left (-\frac {1}{e^{4}}\right )^{\frac {1}{4}} \log \left (-\frac {3^{\frac {1}{4}} {\left (e^{2} x + 2 \, e\right )} \left (-\frac {1}{e^{4}}\right )^{\frac {1}{4}} - {\left (-3 \, e^{2} x^{2} + 12\right )}^{\frac {1}{4}} \sqrt {e x + 2}}{e x + 2}\right ) + 3^{\frac {1}{4}} {\left (i \, e^{2} x + 2 i \, e\right )} \left (-\frac {1}{e^{4}}\right )^{\frac {1}{4}} \log \left (\frac {3^{\frac {1}{4}} {\left (i \, e^{2} x + 2 i \, e\right )} \left (-\frac {1}{e^{4}}\right )^{\frac {1}{4}} + {\left (-3 \, e^{2} x^{2} + 12\right )}^{\frac {1}{4}} \sqrt {e x + 2}}{e x + 2}\right ) + 3^{\frac {1}{4}} {\left (-i \, e^{2} x - 2 i \, e\right )} \left (-\frac {1}{e^{4}}\right )^{\frac {1}{4}} \log \left (\frac {3^{\frac {1}{4}} {\left (-i \, e^{2} x - 2 i \, e\right )} \left (-\frac {1}{e^{4}}\right )^{\frac {1}{4}} + {\left (-3 \, e^{2} x^{2} + 12\right )}^{\frac {1}{4}} \sqrt {e x + 2}}{e x + 2}\right ) - 4 \, {\left (-3 \, e^{2} x^{2} + 12\right )}^{\frac {1}{4}} \sqrt {e x + 2}}{e^{2} x + 2 \, e} \]
(3^(1/4)*(e^2*x + 2*e)*(-1/e^4)^(1/4)*log((3^(1/4)*(e^2*x + 2*e)*(-1/e^4)^ (1/4) + (-3*e^2*x^2 + 12)^(1/4)*sqrt(e*x + 2))/(e*x + 2)) - 3^(1/4)*(e^2*x + 2*e)*(-1/e^4)^(1/4)*log(-(3^(1/4)*(e^2*x + 2*e)*(-1/e^4)^(1/4) - (-3*e^ 2*x^2 + 12)^(1/4)*sqrt(e*x + 2))/(e*x + 2)) + 3^(1/4)*(I*e^2*x + 2*I*e)*(- 1/e^4)^(1/4)*log((3^(1/4)*(I*e^2*x + 2*I*e)*(-1/e^4)^(1/4) + (-3*e^2*x^2 + 12)^(1/4)*sqrt(e*x + 2))/(e*x + 2)) + 3^(1/4)*(-I*e^2*x - 2*I*e)*(-1/e^4) ^(1/4)*log((3^(1/4)*(-I*e^2*x - 2*I*e)*(-1/e^4)^(1/4) + (-3*e^2*x^2 + 12)^ (1/4)*sqrt(e*x + 2))/(e*x + 2)) - 4*(-3*e^2*x^2 + 12)^(1/4)*sqrt(e*x + 2)) /(e^2*x + 2*e)
\[ \int \frac {\sqrt [4]{12-3 e^2 x^2}}{(2+e x)^{3/2}} \, dx=\sqrt [4]{3} \int \frac {\sqrt [4]{- e^{2} x^{2} + 4}}{e x \sqrt {e x + 2} + 2 \sqrt {e x + 2}}\, dx \]
\[ \int \frac {\sqrt [4]{12-3 e^2 x^2}}{(2+e x)^{3/2}} \, dx=\int { \frac {{\left (-3 \, e^{2} x^{2} + 12\right )}^{\frac {1}{4}}}{{\left (e x + 2\right )}^{\frac {3}{2}}} \,d x } \]
Exception generated. \[ \int \frac {\sqrt [4]{12-3 e^2 x^2}}{(2+e x)^{3/2}} \, dx=\text {Exception raised: TypeError} \]
Exception raised: TypeError >> an error occurred running a Giac command:IN PUT:sage2:=int(sage0,sageVARx):;OUTPUT:sym2poly/r2sym(const gen & e,const index_m & i,const vecteur & l) Error: Bad Argument Value
Timed out. \[ \int \frac {\sqrt [4]{12-3 e^2 x^2}}{(2+e x)^{3/2}} \, dx=\int \frac {{\left (12-3\,e^2\,x^2\right )}^{1/4}}{{\left (e\,x+2\right )}^{3/2}} \,d x \]